Okay even though I looked through a ton of posts here and elsewhere, I cannot get a # in front of the following line:
[ -n "$ID" -a "$ID" -le 200 ] && return
I tried several solutions for example:
sed -r "s/[ -n '$ID' -a '$ID' -le 200 ] \&\& return/#[ -n '$ID' -a '$ID' -le 200 ] \&\& return/g"
sed 's/[ -n "$ID" -a "$ID" -le 200 ]/#&/'
And several other ideas based on posts here and elsewhere, but still no result. I only get results like this:
[ -n "$ID" -a "$ID" -le 200 #[ -n '0' -a '0' -le 200 ] ] && return] && return return
#if [ -n "$BASH_VERSION" -o -n "$KSH_VERSION" -o -n "$ZSH_VERSION" ]; then
# [ -x /usr/bin/id ] || return
# ID=`/usr/bin/id -u`
# [ -n "$ID" -a "$ID" -le 200 ] && return
# # for bash and zsh, only if no alias is already set
# alias vi >/dev/null 2>&1 || alias vi=vim
Maybe someone can explain how I can get a # (hashtag) for that particular line given aboven. Probably it's something simple and my best guess is that I am not escaping things correctly?
As mentioned above, I did look up various posts, but I still cannot seem to get this done...